It is possible to print the class layout in Visual C++ using the following command option:

 /d1reportSingleClassLayoutCLASSNAME

Where CLASSNAME is the name of the class you want to print.

The option can be added at the "Command Line" "Additional Options"

Sample: ```cpp struct Base {
int baseInt; virtual void f(){}; virtual ~Base(){} };

struct D1 : public Base { int D1Int; virtual void f1(){}; virtual ~D1(){} };

struct D2 : public Base { int D2Int; virtual void f2(){}; virtual ~D2(){} };

struct D3 : public D1, public D2 { int D3Int; virtual void f(){};
}; ```

 /d1reportSingleClassLayoutD3

Output:

  class D3  size(28):
    +---
    | +--- (base class D1)
    | | +--- (base class Base)
   0    | | | {vfptr}
   4    | | | baseInt
    | | +---
   8    | | D1Int
    | +---
    | +--- (base class D2)
    | | +--- (base class Base)
  12    | | | {vfptr}
  16    | | | baseInt
    | | +---
  20    | | D2Int
    | +---
  24    | D3Int
    +---
  
  D3::$vftableD1:
    | &D3_meta
    |  0
   0    | &D3::f
   1    | &D3::{dtor}
   2    | &D1::f1
  
  D3::$vftableD2:
    | -12
   0    | &thunk: this-=12; goto D3::f
   1    | &thunk: this-=12; goto D3::{dtor}
   2    | &D2::f2
  
  D3::f this adjustor: 0
  D3::{dtor} this adjustor: 0
  D3::__delDtor this adjustor: 0
  D3::__vecDelDtor this adjustor: 0